Problem
A group of two or more people wants to meet and minimize the total travel distance. You are given a 2D grid of values 0 or 1, where each 1 marks the home of someone in the group. The distance is calculated using Manhattan Distance, where distance(p1, p2) = |p2.x - p1.x| + |p2.y - p1.y|.
Example:
Input: 1 - 0 - 0 - 0 - 1 | | | | | 0 - 0 - 0 - 0 - 0 | | | | | 0 - 0 - 1 - 0 - 0 Output: 6 Explanation: Given three people living at (0,0), (0,4), and (2,2): The point (0,2) is an ideal meeting point, as the total travel distance of 2+2+2=6 is minimal. So return 6.Solution
class Solution { public int minTotalDistance(int[][] grid) { Listx = new ArrayList<>(); List y = new ArrayList<>(); for (int i = 0; i < grid.length; i++) { for (int j = 0; j < grid[0].length; j++) { if (grid[i][j] == 1) { x.add(i); y.add(j); } } } Collections.sort(x); Collections.sort(y); int i = 0, j = x.size()-1, res = 0; while (i < j) { res += (x.get(j)-x.get(i)+y.get(j)-y.get(i)); i++; j--; } return res; } }
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Problem A group of two or more people wants to meet and minimize the total travel distance. You are given a 2D grid of values 0 or 1, where each 1 marks the home of someone in the group. The distance ...
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