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[Leetcode-Tree] Sum Root to Leaf Numbers

BigNerdCoding / 2740人閱讀

摘要:解題思路本題要求所有從根結(jié)點(diǎn)到葉子節(jié)點(diǎn)的路徑和,我們用遞歸實(shí)現(xiàn)。結(jié)束條件當(dāng)遇到葉子節(jié)點(diǎn)時(shí),直接結(jié)束,返回計(jì)算好的如果遇到空節(jié)點(diǎn),則返回?cái)?shù)值。

Sum Root to Leaf Numbers
Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.

An example is the root-to-leaf path 1->2->3 which represents the number 123.

Find the total sum of all root-to-leaf numbers.

For example,

    1
   / 
  2   3
The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.

Return the sum = 12 + 13 = 25.

解題思路

本題要求所有從根結(jié)點(diǎn)到葉子節(jié)點(diǎn)的路徑和,我們用遞歸實(shí)現(xiàn)。
結(jié)束條件:當(dāng)遇到葉子節(jié)點(diǎn)時(shí),直接結(jié)束,返回計(jì)算好的sum;如果遇到空節(jié)點(diǎn),則返回?cái)?shù)值0。

2.代碼

public class Solution {
    public int sumNumbers(TreeNode root) {
        return sum(root,0);
    }
    private int sum(TreeNode root, int cur){
        if(root==null) return 0;
        cur=10*cur+root.val;
        if(root.left==null&&root.right==null)
            return cur;
        else
            return sum(root.left,cur)+sum(root.right,cur);
    }
}

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