[LeetCode] 71. Simplify Path

superw 發(fā)布于2019-08-16 14:00 / 2842人閱讀

Problem

Given an absolute path for a file (Unix-style), simplify it.

For example,

path = "/home/", => "/home"
path = "/a/./b/../../c/", => "/c"
path = "/a/../../b/../c//.//", => "/c"        //here: b is cancelled out, a is cancelled out
path = "/a//b////c/d//././/..", => "/a/b/c"   //here d is cancelled out

In a UNIX-style file system, a period (".") refers to the current directory, so it can be ignored in a simplified path. Additionally, a double period ("..") moves up a directory, so it cancels out whatever the last directory was. For more information, look here: https://en.wikipedia.org/wiki...

Corner Cases:

Did you consider the case where path = "/../"?
In this case, you should return "/".
Another corner case is the path might contain multiple slashes "/" together, such as "/home//foo/".
In this case, you should ignore redundant slashes and return "/home/foo".

Solution

class Solution {
    public String simplifyPath(String path) {
        Deque stack = new ArrayDeque<>();
        Set ignore = new HashSet<>(Arrays.asList("", ".", ".."));
        for (String dir: path.split("/")) {
            if (!stack.isEmpty() && dir.equals("..")) stack.pop();
            if (!ignore.contains(dir)) stack.push(dir);
        }
        String res = "";
        while (!stack.isEmpty()) {
            res = "/"+stack.pop()+res;
        }
        if (res.equals("")) return "/";
        return res;
    }
}

GPU云服務(wù)器云服務(wù)器 Simplify V71 LeetCode LeetCode_String

文章版權(quán)歸作者所有，未經(jīng)允許請(qǐng)勿轉(zhuǎn)載,若此文章存在違規(guī)行為，您可以聯(lián)系管理員刪除。

轉(zhuǎn)載請(qǐng)注明本文地址：http://systransis.cn/yun/72713.html

相關(guān)文章

leetcode71. Simplify Path

摘要：標(biāo)題文字簡(jiǎn)化風(fēng)格的絕對(duì)路徑。我們可以首先將所有的內(nèi)容從中分離出來，然后分別處理。這里我們需要用到堆棧的數(shù)據(jù)結(jié)構(gòu)。堆棧有很多種實(shí)現(xiàn)方式，中的類類都可以實(shí)現(xiàn)其功能。我們將讀到的路徑入棧，根據(jù)操作符出棧，最后將棧中剩余的元素組織成路徑返回即可。標(biāo)題文字 Given an absolute path for a file (Unix-style), simplify it. For exa...

darkerXi 2019-08-15 10:37 評(píng)論0 收藏0
71. Simplify Path

摘要：題目解答的規(guī)則如下三種需要跳過的情況當(dāng)遇到時(shí)，需要向前進(jìn)出來的順序是反的，所以加的時(shí)候，把最新出來的路徑加在前面題目：Given an absolute path for a file (Unix-style), simplify it. For example,path = /home/, => /homepath = /a/./b/../../c/, => /cclick to ...

EdwardUp 2019-08-14 14:23 評(píng)論0 收藏0
[Leetcode] Simplify Path 化簡(jiǎn)路徑

摘要：棧法復(fù)雜度時(shí)間空間思路思路很簡(jiǎn)單，先將整個(gè)路徑按照分開來，然后用一個(gè)棧，遇到時(shí)彈出一個(gè)，遇到和空字符串則不變，遇到正常路徑則壓入棧中。注意如果結(jié)果為空，要返回一個(gè)彈出棧時(shí)要先檢查棧是否為空代碼 Simplify Path Given an absolute path for a file (Unix-style), simplify it. For example, path = /...

liangzai_cool 2019-08-14 12:40 評(píng)論0 收藏0
【Leetcode】71. 簡(jiǎn)化路徑

摘要：題目給定一個(gè)文檔的完全路徑，請(qǐng)進(jìn)行路徑簡(jiǎn)化。例如，邊界情況你是否考慮了路徑的情況在這種情況下，你需返回。此外，路徑中也可能包含多個(gè)斜杠，如。文化和社會(huì)被恐懼所塑造，在將來這無(wú)疑也不會(huì)消失。題目給定一個(gè)文檔 (Unix-style) 的完全路徑，請(qǐng)進(jìn)行路徑簡(jiǎn)化。例如，path = /home/, => /homepath = /a/./b/../../c/, => /c 邊界情況:...

liuchengxu 2019-08-19 11:11 評(píng)論0 收藏0
【Leetcode】71. 簡(jiǎn)化路徑

摘要：題目給定一個(gè)文檔的完全路徑，請(qǐng)進(jìn)行路徑簡(jiǎn)化。例如，邊界情況你是否考慮了路徑的情況在這種情況下，你需返回。此外，路徑中也可能包含多個(gè)斜杠，如。文化和社會(huì)被恐懼所塑造，在將來這無(wú)疑也不會(huì)消失。題目給定一個(gè)文檔 (Unix-style) 的完全路徑，請(qǐng)進(jìn)行路徑簡(jiǎn)化。例如，path = /home/, => /homepath = /a/./b/../../c/, => /c 邊界情況:...

afishhhhh 2019-07-30 17:50 評(píng)論0 收藏0