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  • [LeetCode/LintCode] Largest Palindrome Product

    Problem Find the largest palindrome made from the product of two n-digit numbers. Since the result could be very large, you should return the largest palindrome mod 1337. Example Input: 2Output: 987Ex...

    Barry_Ng 評(píng)論0 收藏0
  • 【譯】JS基礎(chǔ)算法腳本:回文檢測(cè)

    ...true,不是則返回false(忽略標(biāo)點(diǎn)符號(hào),大小寫,空格) palindrome(A man, a plan, a canal. Panama) should return true. palindrome(five|\_/|four) 思路1 返回一個(gè)忽略標(biāo)點(diǎn),空格,小寫的新字符串 for-if 來(lái)檢測(cè)前后索引字符是否相等 function palindrome(...

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  • 336. Palindrome Pairs

    ... so that the concatenation of the two words, i.e. words[i] + words[j] is a palindrome. Given words = [abcd, dcba, lls, s, sssll] Return [[0, 1], [1, 0], [3, 2], [2, 4]] The palindromes are [dcbaab...

    Guakin_Huang 評(píng)論0 收藏0
  • Palindrome Pairs & Shortest Palindrome

    Palindrome Pairs 鏈接:https://leetcode.com/problems... 這道題沒想出來(lái)思路,參考了這個(gè)博客的內(nèi)容:http://bookshadow.com/weblog/... 把一個(gè)單詞分為兩個(gè)部分:left, right。right部分是回文的,在words里面找是否有reverse的left。這里的left范圍是...

    CNZPH 評(píng)論0 收藏0
  • [LeetCode/LintCode] Valid Palindrome

    Valid Palindrome Problem Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases. Example A man, a plan, a canal: Panama is a palindrome. race a ca...

    Ververica 評(píng)論0 收藏0
  • [Leetcode] Palindrome Permutation 回文變換

    Palindrome Permutation Given a string, determine if a permutation of the string could form a palindrome. For example, code -> False, aab -> True, carerac -> True. Hint: Consider the palindromes of od...

    svtter 評(píng)論0 收藏0
  • 5. Longest Palindromic Substring

    Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000. Input: babad Output: bab Note: aba is also a valid answer. 暴力算法就是找到所有substring, 每個(gè)...

    APICloud 評(píng)論0 收藏0
  • 214. Shortest Palindrome

    214. Shortest Palindrome 題目鏈接:https://leetcode.com/problems... 找到string從頭開始最長(zhǎng)的palindrome substring:s[0:i+1]那么只要把substring(i+1)的reverse加到s前面就是結(jié)果了。找palindrome substring的過程可以用kmp來(lái)做優(yōu)化,由于reverse(s[0:i+1]) ...

    beita 評(píng)論0 收藏0
  • [LintCode] Palindrome Partitioning II

    ...iven a string s, cut s into some substrings such that every substring is a palindrome. Return the minimum cuts needed for a palindrome partitioning of s. Example Given s = aab, Return 1 since the p...

    funnyZhang 評(píng)論0 收藏0
  • [LeetCode] 9. Palindrome Number

    Problem Determine whether an integer is a palindrome. An integer is a palindrome when it reads the same backward as forward. Example 1: Input: 121Output: trueExample 2: Input: -121Output: falseExplana...

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  • [LintCode] Longest Palindrome

    ...consists of lowercase or uppercase letters, find the length of the longest palindromes that can be built with those letters. This is case sensitive, for example Aa is not considered a palindrome he...

    nicercode 評(píng)論0 收藏0
  • LC 267 Palindrome Permutation II

    Given a string s, return all the palindromic permutations (without duplicates) of it. Return an empty list if no palindromic permutation could be form. For example: Given s = aabb, return [abba, baa...

    lowett 評(píng)論0 收藏0
  • LeetCode 336. Palindrome Pairs

    ... so that the concatenation of the two words, i.e. words[i] + words[j] is a palindrome. Example 1: Input: [abcd,dcba,lls,s,sssll]Output: [[0,1],[1,0],[3,2],[2,4]] Explanation: The palindromes are [d...

    TigerChain 評(píng)論0 收藏0
  • [LeetCode] 647. Palindromic Substrings

    Problem Given a string, your task is to count how many palindromic substrings in this string. The substrings with different start indexes or end indexes are counted as different substrings even they c...

    鄒立鵬 評(píng)論0 收藏0
  • leetcode409.Longest Palindrome

    ...consists of lowercase or uppercase letters, find the length of the longest palindromes that can be built with those letters. This is case sensitive, for example Aa is not considered a palindrome h...

    linkin 評(píng)論0 收藏0

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