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  • Majority Vote Alogrithm(最大投票算法)及其擴(kuò)展

    Boyer-Moore:A Linear Time Majority Vote Alogrithm,這是最基礎(chǔ)的最大投票算法。 原文中提到:decides which element of a sequence is in the majority, provided there is such an element.,但是講的有一些含糊。我再補(bǔ)充一下:在一次投票中,如果某一種投票...

    niceforbear 評(píng)論0 收藏0
  • LeetCode 之 JavaScript 解答第169題 —— 求眾數(shù) I(Majority El

    Time:2019/4/4Title: Majority Element 1Difficulty: easyAuthor: 小鹿 題目:Majority Element 1 Given an array of size n, find the majority element. The majority element is the element that appears more than ...

    hightopo 評(píng)論0 收藏0
  • [LintCode] Majority Number I II III

    Majority Number I Problem Given an array of integers, the majority number is the number that occurs more than half of the size of the array. Find it. Example Given [1, 1, 1, 1, 2, 2, 2], return 1 Chal...

    sPeng 評(píng)論0 收藏0
  • leetcode講解--169. Majority Element

    169. Majority Element Given an array of size n, find the majority element. The majority element is the element that appears more than ? n/2 ? times. You may assume that the array is non-empty and the ...

    LiuRhoRamen 評(píng)論0 收藏0
  • LeetCode[169] Majority Element

    LeetCode[169] Majority Element Given an array of size n, find the majority element. The majority element is the element that appears more than ? n/2 ? times. You may assume that the array is non-empt...

    int64 評(píng)論0 收藏0
  • [Leetcode] Majority Element 眾數(shù)

    Majority Element I Given an array of size n, find the majority element. The majority element is the element that appears more than ? n/2 ? times. You may assume that the array is non-empty and the ma...

    sihai 評(píng)論0 收藏0
  • [LeetCode] Majority Element

    Problem Given an array of size n, find the majority element. The majority element is the element that appears more than ? n/2 ? times. You may assume that the array is non-empty and the majority eleme...

    Shonim 評(píng)論0 收藏0
  • leetcode 169 Majority Element

    題目詳情 Given an array of size n, find the majority element. The majority element is the element that appears more than ? n/2 ? times.You may assume that the array is non-empty and the majority element a...

    tangr206 評(píng)論0 收藏0
  • Leetcode PHP題解--D83 169. Majority Element

    D83 169. Majority Element 題目鏈接 169. Majority Element 題目分析 給定一個(gè)數(shù)組,返回其中出現(xiàn)次數(shù)超過(guò)一半的元素。 思路 用array_count_values函數(shù)計(jì)算元素出現(xiàn)次數(shù),用arsort逆序排序結(jié)果,輸出第一個(gè)即可。 最終代碼

    yagami 評(píng)論0 收藏0
  • LeetCode 之 JavaScript 解答第229題 —— 求眾數(shù) II(Majority E

    Time:2019/4/5Title: Majority Element 2Difficulty: mediumAuthor: 小鹿 問(wèn)題:Majority Element 2 Given an integer array of size n, find all elements that appear more than ? n/3 ? times. Note: The algorithm s...

    BearyChat 評(píng)論0 收藏0
  • MongoDB - Write Concern Reference

    ...在的成員變得可用,這意味著MongoDB會(huì)無(wú)窮盡地阻塞。 majority 確保寫(xiě)操作已成功傳播至大部分投票節(jié)點(diǎn):副本集投票成員中的大部分必須在寫(xiě)操作成功返回前對(duì)寫(xiě)操作進(jìn)行確認(rèn)。這可以讓你避免在應(yīng)用中對(duì)副本集大小做硬編...

    ARGUS 評(píng)論0 收藏0
  • MongoDB 客戶端連接選項(xiàng)

    ...它 >=2 的數(shù)字,如 w:3 表示至少要有 3 個(gè)節(jié)點(diǎn)有數(shù)據(jù)。 w:majority - 和 w:2 一樣,secondary 節(jié)點(diǎn)從 primary 節(jié)點(diǎn)完成數(shù)據(jù)復(fù)制后返回響應(yīng)。不同的是這里并不指定具體的節(jié)點(diǎn)數(shù)量,而是使用 majority 表示大多數(shù),即超過(guò)一半(>1/2)的...

    yexiaobai 評(píng)論0 收藏0
  • MongoDB3.2 之 Rollback講解及避免

    ...驅(qū)動(dòng)的connection level進(jìn)行配置,支持一下值: * w:0 | 1 | n | majority | tag * j:1 * wtimeout: millis w:0 unacknowledged驅(qū)動(dòng)只是一味的進(jìn)行寫(xiě)入操作,不會(huì)關(guān)心是否寫(xiě)入成功,也就是mongo不會(huì)返回操作結(jié)果 w:1 Acknowledged看圖我們很容易理解...

    go4it 評(píng)論0 收藏0
  • 靈雀云CTO陳愷:從“鴻溝理論”看云原生,哪些技術(shù)能夠跨越鴻溝?

    ...Innovator)、早期使用者(Early adopters)、早期大眾(Early majority)、晚期大眾(Late majority)、落后者(Laggard)。 在Early adopters和Early majority之間有個(gè)巨大的鴻溝(Chasm),每個(gè)新技術(shù)都會(huì)經(jīng)歷鴻溝,大多數(shù)失敗的產(chǎn)品也都是在鴻...

    hss01248 評(píng)論0 收藏0
  • 淺層次分析鏈?zhǔn)秸{(diào)用的部分原理

    ...節(jié)點(diǎn) }else if(String(domName)[0] === .){ this.total = majority;//表示選擇器獲得節(jié)點(diǎn)為多數(shù),調(diào)用其他方法的時(shí)候需要循環(huán) this.init = document.getElementsByClassName(new String(domName).substring(1,new Stri...

    Sike 評(píng)論0 收藏0

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